The ratio of the distance covered by a cyclist to travel along the outer and the inner boundaries of a circular path is 23:22.If the path is 5 m wide,
Find the diameter of inner circle & Find the Area of outer circle in m^2
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Answer:
Let the radius of inner perimeter be r
1
and the outer perimeter be r
2
So,
2r
1
π
2r
2
π
=
22
23
⇒r
2
=
22
23
r
1
Now from the question, we have
r
2
−r
1
=5
22
23
r
1
−r
1
=5
⇒r
1
=110
and r
2
=115
Area of path enclosed between two circles are,
=π(r
2
2
)−π(r
1
2
)
=π(115
2
−110
2
)
=3535.71
Thus the area of path enclosed between the two circles is 3535.71 sq. m.
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