the ratio of the efficiencies A,B and C is 7:5:8 working together they can complete a piece of work in 42 days.B and C worked together for 21 days and the remaining work was completed by A aline The whole work was completed in.
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The whole work will be completed in 102 days
1) To find the total number of days in which the total work is completed we have to find the total work which have to be done.
2) A : B : C = 7 : 5 : 8 = 20 ( Total efficiencies)
- Total Work= Total Efficiency × Days
= 20×42
= 840
- B & C works for 21 days.
- Work Done = 21(5+8)
= 21 × 13
= 273
- Work Left= 84--273 = 567
- Remaining Work done by A= 567/7= 81 days
- Total Work completed in 81+21 = 102 days.
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