Question

The ratio of the electric flux linked with shell A and shell

B in the diagram shown below is​
will give brainliest for 1st answer

Answer 1

To find:

The ratio of the electric flux linked with shell A and shell B in the diagram?

Calculation:

The electric flux linked with shell can be calculated from GAUSS' LAW as follows:

For shell A:

$\therefore \: \phi_{A} = \dfrac{ q_{enclosed}}{ \epsilon_{0}}$

$\implies\: \phi_{A} = \dfrac{ q}{ \epsilon_{0}}$

For shell B:

$\therefore \: \phi_{B} = \dfrac{ q_{enclosed}}{ \epsilon_{0}}$

$\implies\: \phi_{B} = \dfrac{ q}{ \epsilon_{0}}$

So, both the flux are same.

Hence, final answer:

$\therefore \: \phi_{A} = \phi_{B}$

Answer 2

Answer:

1:2

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