Question

The ratio of the energies of the hydrogen atom in its first to second excited state is option is 1) 1/4 2) 4/9 3) 9/4 4) 4

Answer 1

$E = k  \frac{Z^{2} }{n^{2} }$

$\frac{E_{1} }{E_{2} } = \frac{n_{2}^{2} }{n_{1} ^{2}}$

$\frac{E_{1} }{E_{2} }  = 4$