The ratio of the energies of the hydrogen atom in its first to second excited states is(a) 1/4(b) 4/9(c) 9/4(d) 4
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Answer:
C) 9/4
Explanation:
Let the first excited state in the second orbit (n = 2)
Let the second excited state in the third orbit (n = 3)
Assuming the semi classical model of H like atoms will be -
En = -13.6Z²/n²
Energy in the ground state of H will be given by n = 1 and Z = 1 in the formula, i.e E1 = -13.6
Thus, on calculating
E = 13.6/n²
E2/E3 = (3/2)²
E2/E3 = 9/4
Thus, the ratio of the energies of the hydrogen atom in its first to second excited states will be 9/4
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