Question

The ratio of the energies of two different radiation whose frequencies are 3*10^ 14hz and 5*10^14.

Answer 1

Answer:

E=hv(nu)

E=6.626×10^-34×5×10^14 =33.13×10^-20

E=33.13×10^-20×6.022×10^23. =199.50×10^-3

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