Chemistry, asked by pranayakonda4444, 11 months ago

The ratio of the energy required to remove electron
from second orbit and third orbit of Het ion is
(1) 2:3
(2) 1:1
(3) 9:4
(4) 4:1​

Answers

Answered by aasthuboopal
2

Answer:

3

Explanation:

energy is directly proportional to Z2 and inversely proportional to n2 here Z is same

Similar questions