Question

the ratio of the equal side to its base is 3 ratio 2 find the area of triangle the perimeter of an isosceles triangle is 32 CM

Answer 1

let the total length of two equal sides be 3x+3x
 the length of the base be 2x
here x is a ratio constant

BTP
=>3x+3x+2x=32
=>8x=32
=>x=32/8
=>x=4
total length of the to equal sides = (3x4)+(3x4)
                                                    =12+12=24
length of base=2x4=8
area of the triangle=1/2x(8)^2cm
                              =1/2x64cm
                              =32sq cm
ans:32sqcm

Answer 2

Answer:

hii,I hope this will help you

as the isosceles triangle has two equal sides

ratio of side and base=3/2

then the equal side be 3x and base be 2x

then

perimeter=3x+3x+2x

32=8x

4=x

then equal side=4*3=12 and base=4*2=8

then area of isosceles triangle by heron formula

semi perimeter=32/2=16cm

√{16(16-12)(16-12)(16-8)

√{16*4*4*8}

4*2*2*2√2

32√2 is the area of triangle