Question

The ratio of the frequencies of the long wavelength limits of Lyman and Balmer series of hydrogen spectrum is(a) 27 : 5(b) 5 : 27(c) 4 : 1(d) 1 : 4

Answer 1

I hope is a right answer

Answer 2

Answer:

The ratio of the frequencies of the long wavelength limits of Lyman and Balmer series of hydrogen spectrum is 27:5

(a) is correct.

Explanation:

The frequency of hydrogen atom spectrum  in the spectral lines corresponding to transition of electron from higher energy state to lower energy state is given by:

$\nu=R(\dfrac{1}{n_{f}^2}-\dfrac{1}{n_{i}^2})$

Where, $n_{i}$= initial state

$n_{f}$= final state

The ratio of the frequencies of the long wavelength limits of Lyman and Balmer series of hydrogen spectrum is

$\dfrac{\nu_{L}}{\nu_{B}}=\dfrac{\dfrac{1}{1^2}-\dfrac{1}{2^2}}{\dfrac{1}{2^2}-\dfrac{1}{3^2}}$

$\dfrac{\nu_{L}}{\nu_{B}}=\dfrac{\dfrac{3}{4}}{\dfrac{5}{36}}$

$\dfrac{\nu_{L}}{\nu_{B}}=\dfrac{27}{5}$

Hence, The ratio of the frequencies of the long wavelength limits of Lyman and Balmer series of hydrogen spectrum is 27:5