Question

The ratio of the intensities of minima to maxima in an interference pattern of Young's
double slit experiment is 9:25. What does it imply about the experimental set
up ? Explain your answer in numerical terms.​

Answer 1

Answer:

Wave Optics. The ratio of the intensities at minima to maxima in the interference pattern is 9 : 25. ... Intensity is proportional to width of slit. So, amplitude a1 and a2 is proportional to the square root of the width of the slit.

Answer 2

Explanation:

If the width of the slits are A₁ and A₂, the amplitude will also be A1 and A2.

The maximum amplitude, A' will happen when constructive interference happens

A' = (A₁ + A₂)

The maximum amplitude, A will happen when destructive interference happens

A = (A₁ - A₂)

We know that intensity is proportional to the square of amplitude.

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