Physics, asked by aniketotari9050, 1 year ago

The ratio of the intensity at the centre of a bright fringe to the intensity at a point one quarter of the distance between two fringes from the centre is :

Answers

Answered by Anonymous
25
We have the formula for the intensity at a point in the interference pattern,

I=4I0cos2(ϕ/2) … … … … (1)

I0 is the intensity due to either of the slit and ϕ is the phase difference between the waves emitted from the two slits.

At the centre of the bright fringe the two waves are in phase (ϕ=0) and hence the intensity,

I1=4I0

Since the phase difference between the successive fringes is 2π hence the phase difference between the centre of a bright fringe and at a point one quarter of the distance between the two fringes away is 2π/4=π/2. This then from equation (1) gives the intensity I2 at that point,

I2=4I0cos2(π/4)=2I0

And, I1/I2=2
Answered by Anonymous
16

Explanation:

since the ratio of the intensity at the centre of bright fringe to the intensity at a point one quarter of the distance between two princes from the centre.... !! ....

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