Question

The ratio of the kinetic energies of equal
number of moles of H, and He at the same
temperature is

Answer 1

Answer:

ok

Explanation:

We take first and second bodies as A and B. and take VA and VB are velocities of them respectively.

Momentum of both are equal.

We can write as below.

mVA =2mVB

VA = 2 VB

KA = kinetic energy of body A

KB = kinetic energy of body B

Now we find ratio of them

KA : KB

1/2m(VA)^2 : 1/2*2m(VB)^2

VA = 2VB

1/2m(2VB)^2 : 1/2*2m(VB)^2

4 : 2

2 : 1

pls mark brainliest