Question

the ratio of the largest to shortest wavelength in balmer series of hydrogen spectra is .. plz help me in these kind of numerical ..​

Answer 1

Solution :- Shortest Transition of the Balmer series is from n₁ = 2 and n₂ = 3.

Longest Transition of the Balmer Series is from n₁ = 2 and n₂ =infinity

Note:- Shortest Transition means the longest wavelength and the Longest Transition means the shortest wavelength.

➡By Using the Rydberg Equation for Hydrogen Atom,

1/λ₁ = R(1/n₁² - 1/n₂²)

1/λ₁ = R(1/4 - 1/9)

1/λ₁ = R(5/36)

λ₁ = 36/5R

or,  1/λ₂ = R(1/n₁² - 1/n₂²)

=> 1/λ₂ = R(1/4 - 1/Infinity²)

=> 1/λ₂ = R/4

=> λ₂ = 4/R

then, λ₁/λ₂ = 36/5R ÷ 4/R

 λ₁/λ₂ = 9/5

λ₁ : λ₂ = 9 : 5 Answer ✔

Answer 2

hello mam ..iam hear agen ..

Dinesh