Question

The ratio of the length AB and the length AC is 2:9. Find by how much does length BC exceed AB (in cm) by observing the given diagram.​

Answer 1

Answer:

The shortest length is 7 cm.

Step-by-step explanation:

BC = 2 AB - 3  ----(1)

AC = AB + 9 ----(2)

AC + BC + AB = 34  ----(3)

Putting value of BC and AC in equation (3).

2AB - 3 + AB + 9 + AB = 34

4 AB + 6 = 344 AB =  34 - 6

AB  = 28 / 4 = 7 cm

Putting value of AB in equation (1) and (2)

BC = 2 (7) - 3      AC = 7 + 9

BC = 14 - 3          AC = 16

BC = 11                AC = 16

Hence the shortest length is 7 cm.

Also learn more

The sides of a triangle are 5 cm; 7 cm and 10 cm. find the length of the median to the longest side.

?

https://brainly.in/question/5791174

Answer 2

Ratio

Given:

Ratio of length of AB to length of AC is 2:9

To Find:

By how much length of BC exceed AB

Explanation:

A,B,C are the points lying on the same line as shown in figure.

We can infer that length of AB and length of BC will be the length of AC.

As from the ratio given,

let the length of AB be $2x$.

let the length of AC be $9x$.

So, the length of BC will be $AC-AB=(9x-2x)=7x$

In the figure it is denoted that length if AB is 8cm.

So,

$2x=8\\=>x=4$

Hence , length of AB= 8 cm

length of AC= $9x= 9\times4=36$ cm

length of BC= $7x=7\times 4=28$ cm

∴BC exceed AB by $(28-8)=20cm$