The ratio of the length and breadth of the rectangle is 18:7 and the area of the rectangle is 126 sq.Cm.What is the perimeter of the rectangle
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Given: Ratio of the length and breadth is 18:7 and area of the rectangle is 126cm^2.
To find: Perimeter of the rectangle
Answer:
Formula to find the area of a rectangle = Length*Breadth.
Let us take the length to be 18x and breadth to be 7x.
Area of the rectangle is 18x*7x.
Since area is given, 126cm^2,
126 = 18x*7x
126 = 126x
x = 126/126
x = 1
Length is 18*1 = 18cm and Breadth is 7*1 = 7cm.
Now to find the perimeter.
Formula to find the perimeter of a rectangle = 2(Length + Breadth).
Since we know the length and the breadth,
Perimeter = 2(18 + 7)
= 2*25
= 50cm
Hope it helps :)
DaIncredible:
Great!!
Answered by
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heya buddy ur ans
let length and Breadth be as 18x and 7x
area = 126 sq.cm
now
as we know
area = l*B
126= 18x*7x
126=126x^2
126/126=x^2
1= x ^2
1=x
now equate it
18x=18*1
= 18
Length=18cm
Breadth =
7x
7*1=7cm
perimeter
2(l+B)
=2(18+7)
=2(25)
=50cm
let length and Breadth be as 18x and 7x
area = 126 sq.cm
now
as we know
area = l*B
126= 18x*7x
126=126x^2
126/126=x^2
1= x ^2
1=x
now equate it
18x=18*1
= 18
Length=18cm
Breadth =
7x
7*1=7cm
perimeter
2(l+B)
=2(18+7)
=2(25)
=50cm
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