the ratio of the length of the parallel sides of a Trapezium is 3 is to 2 the shortest distance between them is 15 CM if the area of the trapezium is 450 CM square find the sum of the length of the parallel sides
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Solve this problem using the formula i have given
1/2 multiplicated by h xsum of parallel sides
1/2 multiplicated by h xsum of parallel sides
Answered by
12
Given :
The ratio of the length of the parallel sides of a Trapezium is 3 is to 2 the shortest distance between them is 15 CM
To Find :
If the area of the trapezium is 450 CM square find the sum of the length of the parallel sides
Solution:
The ratio of the length of the parallel sides of a Trapezium is 3:2
Let the ratio be x
Parallel sides are 3x and 2x
Shortest distance between parallel lines = 15 cm
Area of trapezium =
Area of trapezium =
We are given that the area of trapezium is 450 sq.cm.
So,
Parallel sides :
3x=3(12)=36 cm
2x=2(12)=24 cm
Sum of parallel sides = 36+24=60 cm
Hence The sum of the length of the parallel sides is 60 cm
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