Question

the ratio of the length of the parallel sides of a Trapezium is 3 is to 2 the shortest distance between them is 15 CM if the area of the trapezium is 450 CM square find the sum of the length of the parallel sides

Answer 1

Solve this problem using the formula i have given
1/2 multiplicated by h xsum of parallel sides

Answer 2

Given :

The ratio of the length of the parallel sides of a Trapezium is 3 is to 2 the shortest distance between them is 15 CM

To Find :

If the area of the trapezium is 450 CM square find the sum of the length of the parallel sides

Solution:

The ratio of the length of the parallel sides of a Trapezium is 3:2

Let the ratio be x

Parallel sides are 3x and 2x

Shortest distance between parallel lines = 15 cm

Area of trapezium =$\frac{1}{2}(\text{Sum of parallel sides}) \times height$

Area of trapezium = $\frac{1}{2}(3x+2x)(15)$

We are given that the area of trapezium is 450 sq.cm.

So, $\frac{1}{2}(3x+2x)(15)=450\\5x=\frac{450 \times 2}{15}\\x=\frac{450 \times 2}{15 \times 5}\\x=12$

Parallel sides :

3x=3(12)=36 cm

2x=2(12)=24 cm

Sum of parallel sides = 36+24=60 cm

Hence The sum of the length of the parallel sides is 60 cm