Question

The ratio of the length of two pendulum
is 4, what it is the ratio of their time period​

Answer 1

Answer:

4 multiply by 24

Explanation:

divide it by 24

Answer 2

Answer:

Time period of simple pendulum is given by

Time period of simple pendulum is given byT=

Time period of simple pendulum is given byT= 2π

Time period of simple pendulum is given byT= 2π g

Time period of simple pendulum is given byT= 2π gl

Time period of simple pendulum is given byT= 2π glL

Time period of simple pendulum is given byT= 2π glL1

Time period of simple pendulum is given byT= 2π glL1= 6 and

Time period of simple pendulum is given byT= 2π glL1= 6 andL

Time period of simple pendulum is given byT= 2π glL1= 6 andL2

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1=

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T2

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T2T

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T2T1

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T2T1=

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T2T1= 2

Time period of simple pendulum is given byT= 2π glL1= 6 andL2=256∴ T2T1= L2L1⇒ T2T1= 21