The ratio of the lengths of parallel sides of a trapezium is 3:5. The distance between them is 12 cm. If he area of the trapeziurn is 720 cm, find the lengths of the parallel sides
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Let the lengths be 3x and 5x. Then the area is given by
(1/2)(3x+5x)(12)=720
8x=720/6=120
x=120/8=15
sides are 3×15=45 and 5×15=75
I have always told that whenever ratio is given, there is a missing number which has to be found out. In the present case it is x which has been found to be 15.
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