The ratio of the lengths of parallel sides of a trapezium is 3:5. The distance between them is 12 cm. If the area of the trapezium is 720 cm square, find the lengths of the parallel sides.
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area =720cm²
height=12cm
let the parallel sides be 3x and 5x
area=1/2(Sum of parallel sides) height
720=1/2(3x+5x)12
720=6×8x
720/6=8x
x=120/8
x=15
so the sides will be
=3×x
=3×15
=45cm
=5×x
=5×15
=75cm
here is your answer hope it helps you enough my friend, Happ New year
height=12cm
let the parallel sides be 3x and 5x
area=1/2(Sum of parallel sides) height
720=1/2(3x+5x)12
720=6×8x
720/6=8x
x=120/8
x=15
so the sides will be
=3×x
=3×15
=45cm
=5×x
=5×15
=75cm
here is your answer hope it helps you enough my friend, Happ New year
Urvashigaur02:
wlcm
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