Question

The ratio of the lengths of the parallel sides of a trapezium is 4:1 the distance between them is 10cm if the area of the

trapezium is 500 cm2 .find the lengths of the parallel sides​

Answer 1

Answer:

Answer is

The other parallel side =4x=4×20=80cm (∵ parallel sides are in 4:1)

Step-by-step explanation:

ANSWER

Area of the trapezium =500cm

2

Distance between the parallel sides of the trapezium =10cm

Ratio of the lengths of the parallel sides of the trapezium =4:1

Let the lengths of the parallel sides of the trapezium be 4x and xcm.

Area of the trapezium =

2

1

(a+b)×h

⇒500=

2

1

(x+4x)×10

⇒500=(x+4x)5

⇒500=25x

⇒x=

25

500

=20cm

∴ One parallel side =20cm

∴ The other parallel side =4x=4×20=80cm (∵ parallel sides are in 4:1)

Answer 2

Answer:

$\huge{\boxed{\rm{\red{80cm,20cm}}}}$

Step-by-step explanation:

Given:-

The ratio of the lengths of the parallel sides of a trapezium is 4:1 the distance between them is 10cm if the area of the trapezium is 500cm² .

To find:-

find the lengths of the parallel sides.

Solution:-

The ratio of the lengths of the parallel sides of a trapezium is 4:1

Let they be a=4x and b=x

the distance between them =h= 10cm

Area of the Trapezium=h(a+b)/2 sq.units

=>10(4x+x)/2 sq.cm

=>10(5x)/2 cm²

=>5(5x) cm²

=>25x cm²

According to the given problem,

Area of the given Trapezium=500cm²

=>25x=500

=>x=500/25

=>x=20

=>4x=4(20)=80

a=4x=80cm

b=x=20cm

Answer:-

The lengths of the parallel sides are 80cm and 20cm