Physics, asked by nixark9999, 1 day ago

The ratio of the magnitudes of the magnetic field of a current carrying coil at the centre and at an axial point for which x = R√3

Answers

Answered by vaidyamadhura934
0

Answer:

this is my answer key see if it is useful for you

Explanation:

Correct option is

D

8:1

REF. Image.

B

c

=

2R

M

a

I

B

axial

=

2(R

2

+(

3

R)

2

)

3/2

M

0

IR

2

=

2R

3

(4)

3/2

M

0

IR

2

B

axial

B

C

=

(M

0

I/2R)(

8

1

)

(M

0

I.2R)

B

axial

B

c

=

1

8

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