The ratio of the magnitudes of the magnetic field of a current carrying coil at the centre and at an axial point for which x = R√3
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Answer:
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Explanation:
Correct option is
D
8:1
REF. Image.
B
c
=
2R
M
a
I
B
axial
=
2(R
2
+(
3
R)
2
)
3/2
M
0
IR
2
=
2R
3
(4)
3/2
M
0
IR
2
B
axial
B
C
=
(M
0
I/2R)(
8
1
)
(M
0
I.2R)
B
axial
B
c
=
1
8
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