Question

the ratio of the mass of the moon to that of the earth is 1:81 . If the radius of the moon is assumed to be 1/4 th of that of the earth then what is the acceleration due to gravity on the surface of the moon in terms of that on earth's surface? Hence find the escape velocity from the surface of the moon in terms of that from earth's surface.​

Answer 1

☆•QUESTION•☆

the ratio of the mass of the moon to that of the earth is 1:81 . If the radius of the moon is assumed to be 1/4 th of that of the earth then what is the acceleration due to gravity on the surface of the moon in terms of that on earth's surface? Hence find the escape velocity from the surface of the moon in terms of that from earth's surface.

☆ANSWER☆

Acceleration due to gravity ,

Acceleration due to gravity ,g=R2GMeAtearth,ge=re2GMm,andatmoongm=Rm2GMm∴gmge=MmMe(RmRe)2⇒gm=ge×MeMm×(RmRe)

ANSWER= 1.65meters/per sec

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