Math, asked by baviiiiii, 7 months ago

The ratio of the number of boys to girls in three classes are 7:5,3:2 and 1:1 respectively. 50% of the boys and 40% of the girls of the first class, 60% of the boys of the second class and 50% of the girls of the
third class join the sports club. There are 51 students in the sports club and 91 students who are not in the sports club from these three classes. If there are 6 more students in the second class than in the third
class, what is the total number of girls in the three classes?​

Answers

Answered by amitnrw
1

Given :  The ratio of the number of boys to girls in three classes are 7:5,3:2 and 1:1 respectively. 50% of the boys and 40% of the girls of the first class, 60% of the boys of the second class and 50% of the girls of the  third class join the sports club.  

To find :  the total number of girls in the three classes

Solution:

Lat say Class 1  Students = 12A

Boys = 7A  & Girls =  5A

Class 2 Students  =  10B

Boys = 6B  & Girls  =  4B

Class 3 Students  = 10B - 6

Boys = 5B-3   & Girls = 5B - 3  

Total = 12A + 20B - 6

51 + 91 = 142  Total studnets

=> 12A + 20B - 6  = 142

=> 12A + 20B  = 148

=> 3A + 5B = 37

Join Club =  (50/100)(7A) + (40/100)5A  + (60/100)6B  +  (50/100)(5B-3)  = 51

=> 3.5A + 2A  + 3.6B + 2.5B - 1.5 = 51

=> 5.5A + 6.1B  = 52.5

3A + 5B = 37        => 165A + 275B   = 2035

55A  + 61 B  = 525 => 165A + 183B = 1575

=>  92B = 460

=> B = 460/92  

=> B = 5

=> A = 4

total number of girls in the three classes 5A + 4B + 5B - 3

= 5A + 9B - 3

= 5(4) + 9(5) - 3

= 20 + 45 - 3  

=  62  

62 girls in all three classes

Class 1   - Boys =  28   Girls  = 20     =    48

Class 2   Boys =   30    Girls       20    = 50

Class  3  Boys     22      Girls    22    =   44

Join Club  =  14  + 8  + 18 + 11  = 51

62 girls in all three classes

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