Question

the ratio of the number of chocolates with A and B is 3:4 .if A gives four chocolates to B, the ratio of the no. of chocolates with them becomes 5:9 .how many chocolates did A have initially?​

Answer 1

Let the ratio be 3x and 4x
So,
=> 3x-4/4x+4 = 5/9
=> 9(3x-4) = 5(4x+4). [cross multiply]
=> 27x-36 = 20x+20
=> 27x-20x = 20+36
=> 7x = 56
=> x = 56/7
=> x = 8

So,
No. of chocolates A has = 3x
= 3(8)
= 24
No. of chocolates B has = 4x
= 4(8)
= 32


Therefore, A had 24 chocolates and B had 32 chocolates.

So, the no. of chocolates they have currently => A = 24-4 = 20
and B = 32+4 = 36

Therefore, no. of chocolates A has currently is 20 chocolates, and B has 36 chocolates.