The ratio of the number of electrons in the N shell of A and M shell of B with the atomic numbers 40 and 32 is
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Answer:
5:9
Explanation:
The electronic configuration of element A with atomic number 40 is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d2 5s2
K- 2 L - 8 M- 18 N - 10 O- 2
The electronic configuration of element B with atomic number 32 is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p2
K- 2 L - 8 M- 18 N- 4
The ratio of number of electrons in N shell of element A M shell of element B = 10:18 = 5:9
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