Physics, asked by gdeepa2009, 1 month ago

The ratio of the number of electrons in the N shell of A and M shell of B with the atomic numbers 40 and 32 is

Answers

Answered by himanshikaushik8
0

Answer:

5:9

Explanation:

The electronic configuration of element A with atomic number 40 is

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d2 5s2

K- 2 L - 8 M- 18 N - 10 O- 2

The electronic configuration of element B with atomic number 32 is

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p2

K- 2 L - 8 M- 18 N- 4

The ratio of number of electrons in N shell of element A M shell of element B = 10:18 = 5:9

Similar questions