Question

The ratio of the number of neutrons present in one atom each of C and Si with respect to mass number
of 12 and 28 respectively is :
(A) 3:7
(B) 7:3
(C) 3:4
​

Answer 1

Answer:

A) 3:7

Explanation:

to find number of neutron we have to

do

mass number -atomic number

so C= 12-6= 6

Si = 28- 14 = 14

ratio is 3:7

Answer 2

Answer:

Answer is option A

Explanation:

Given,

Mass number of C=12

Mass number of Si=28

We know that,

Number of neutrons =Mass number-Atomic number

So,

Number of neutrons in C=12-6=6

number of neutrons in Si=28-14=14

Therefore, Ratio = 3:7

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