Question

the ratio of the number of oranges with Janson and tom is 21:11.if janson gives ton 30 oranges both will have equal number of oranges. find the initial number of oranges with tom​

Answer 1

Answer:

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Answer 2

Answer:

The answer to the given question is The oranges with tom is 66.

Step-by-step explanation:

Given :

The ratio of oranges with mansion and tom is 21:11.

Janson gives 30 oranges to tom so that both will have an equal number of oranges.

To find:

we have to find the number of oranges initially with Tom.

Solution :

let the initial number of oranges with Janson and Tom will be x and y respectively.

Based on the given condition, we have to create an equation.

$\frac{x}{y} = \frac{21}{11}$

on cross multiplying, we get the values as

$11x = 21y - - - (1)$

the value of y will be

$y = \frac{11x}{21}$

It is given that Janson gives 30 oranges to tom

so Janson loses 30 and tom gains 30.

$(x - 30) = (y + 30)$

$(x - y) = 30 + 3 0 = 60$

we have to substitute the value of y in the above expression we get the answer as

$x - \frac{11x}{21} = 60$

$\frac{21x - 11x}{21} = 60$

on simplification, we get the value as

$\frac{10x}{21} = 60 \\ 10x = (21) \times (60) \\ 10x = 1260 \\ x = \frac{1260}{10} \\ x = 126$

Substitute the value of x in the first equation, we get the value of y as

$y = \frac{11(126)}{21} \\ y = 11 \times \\ y = 66$

It is found that the value of y is obtained as 66.

Therefore, initially, the tom has 66 oranges.

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