Math, asked by tejask11, 9 months ago

The ratio of the number of sides of two regular polygons is 1 : 2, and the ratio of the

sum of their interior angles is 3 : 8. Find the number of sides in each polygon​

Answers

Answered by MaheswariS
24

Answer:

sides of the given polygon are 5 and 10

Step-by-step explanation:

\text{Let }n_1\text{ and }n_2\text{ be the number of sides the given two polygons}

\text{Given:}

n_1:n_2=1:2

\implies\,n_1=k\text{ and }n_2=2k

\textit{We know that, the sum of interior angles of a regular polygon is }\bf\,(n-2)\times\,180^{\circ}

\text{As per given data, }

(n_1-2)\times\,180^{\circ}:(n_2-2)\times\,180^{\circ}=3:8

\implies\frac{(n_1-2)\times\,180^{\circ}}{(n_2-2)\times\,180^{\circ}}=\frac{3}{8}

\implies\frac{n_1-2}{n_2-2}=\frac{3}{8}

\implies\frac{k-2}{2k-2}=\frac{3}{8}

\implies\frac{k-2}{2(k-1)}=\frac{3}{8}

\implies\frac{k-2}{k-1}=\frac{3}{4}

\implies\,4k-8=3k-3

\implies\,k=5

\therefore\,n_1=5\text{ and }n_2=10

Answered by suchindraraut17
3

Answer:

The number of sides of each polygon is 3 and 6.

Step-by-step explanation:

Since, it is being given that ;

The ratio of the number of sides of two regular polygons is 1 : 2;

Let,     n1 : n2  =  1 : 2

\frac{n1}{n2}  =  \frac{1}{2}

the ratio of the  sum of their interior angles is 3 : 8;

Let , the sum of the interior angles be A1 and A2 respectively;

So,       A1 : A2 =  3 : 8

∴     \frac{A1}{A2}  =  \frac{3}{8}

Since , the formula for sum of the interior angle of the polygon is \frac{(n - 2)  \times  180}{n}

∴  A1  =  \frac{(n1 - 2)  \times  180}{n1}...........(1)

&

   A2 =  \frac{(n2 - 2)  \times  180}{n2},,,,,,,,,,(2)

Dividing  (1) and (2)

∴  \frac{A1}{A2} = \frac{(n1 - 2) \times 180 }{n1} \times\frac{n2}{(n2 -2) \times 180}

\frac{3}{8}  = \frac{(n1-2) \times n2}{(n1-2) ]\times n1}

\frac{3}{8}  = 2 \times \frac{n1 - 2}{n2 -2}

3 \times n2  - 6 = 16 \times (n1-2)

Putting,    n2 = 2n1 ;

We get;

6 \times n1 - 16 \times n1 = -26

∴ We get n1 = 2.6 ≅ 3

∴ Number of sides of first polygon is 3.

Sincen2 = 2 \times n1

n2 = 2 \times  3

n2 = 6

∴ Number of sides of second polygon is 6.

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