The ratio of the outer and inner perimeters of a circular path is 23 : 22. If the path is 5 metres wide, the diameter of the inner circle is
(a)55 m
(b)110 m
(c)220 m
(d)230 m
Answers
Answer:
The Diameter of inner circle is 220 m.
Among the given options option (c) 220 m is the correct answer.
Step-by-step explanation:
Let outer and inner circumference of the circular path be C1 & C2 and the outer radius of the circular path be ‘R’ and inner radius be ‘r’
Given :
Ratio of the outer and inner Perimeters of the circular path,C1 : C2 = 23 : 22
Width of circular path, (R - r) = 5 …….(1)
Circumference of a circle = 2πr
C1 : C2 = 23 : 22
2πR : 2πr = 23 : 22
R : r = 23 : 22
22R = 23r
R = 23r/22
On putting the value of R in eq 1
R - r = 5
23r/22 - r = 5
(23r - 22r)/22 = 5
r = 22 × 5
r = 110 m
Radius of a inner circle, r = 110 m
Diameter of inner circle , d = 2 × r
d = 2 × 110
d = 220 m
Diameter of inner circle = 220 m
Hence, the Diameter of inner circle is 220 m.
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Answer
Let R = 23x and r = 22x
It is given that the width of the path is 5 m wide
here, R – r = 5 m
- 23x – 22x = 5 m
- x = 5 m
The external diameter of the circular road = 2 × 23 × 5 m = 230 m
The diameter of the circular road = 2 × 22 × 5 m = 220 m
Answer=220m