Question

the ratio of the perimeter to the breadth of a rectangle is 5:2. Find the length to the breadth please i request you to answer plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Answer 1

Answer:

Let length =5x and breadth=2x

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14x

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow,

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, A

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP =

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 3

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x =

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x = 3

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x = 31

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x = 31

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x = 31 ⇒x=4.2

Let length =5x and breadth=2xArea of rectangle=5x×2x=10x 2 Perimeter of rectangle=2(l+b)=2×(5x+2x)=14xNow, AP = 31 ⇒ 10x 2 14x = 31 ⇒x=4.2∴Length of rectangle=5×4.2=21 units.