Question

The ratio of the present age of Dave and Daniel is 4:7.Six years later the sum of their ages is 3:4.What will be the present age of Dave and
Daniel

Answer 1

Given:

• The ratio of the present age of Dave and Daniel is 4:7.

• Six years later ,the sum of their ages is 3:4.

To find out:

Find their Present ages.

Solution:

Let Dave's Present age be 4x years and that of Daniel's age be 7x years .

Six years later,

Dave's age = ( 4x + 6 ) years

Daniel's age = ( 7x + 6 ) years

By the given conditions,

( 4x + 6 ) : ( 7x + 6 ) = 3 : 4

$\rightarrow \frac{4x + 6}{7x + 6} = \frac{3}{4}$

$\rightarrow4(4x + 6) = 3(7x + 6)$

$\rightarrow16x + 24 = 21x + 18$

$\rightarrow16x - 21x = 18 - 24$

$\rightarrow - 5x = - 6$

$\rightarrow \: x = \frac{ 6}{5}$

Dave's age = 4x = 4 × 6/5 = 24/5 = 4.8 years

Daniel's age = 7x = 7 × 6/5 = 42/5 = 8.4 years

Answer 2

Giver:

• The ratio of the present age of Dave and Daniel is 4:7

• Six years later, the sum of their ages is 3:4

To find out:

Find their present ages.

Solutions:

Let Dave's present age be 4x years and that of Daniel's age be 7x years.

Six years later

Dave's age = (4x + 6) years

Daniel's age = (7x + 6) years

By the given conditions.

(4x + 6):(7x + 6) = 3:4

4x + 6 / 7x + 6 = 3/4

4(4x + 6) = 3(7x + 6)

16x - 24 = 21x + 18

-5x = -6

x =6/5

Dave's age = 4x = 4 × 6/5 =24/5 =4.8 years.

Daniel's age = 7x = 7 × 6/5 = 42/5 = 8.4 years.

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