Math, asked by swapnajitrock9425, 10 months ago

The ratio of the present age of Mitali to that of Shabnam is 4: 7.If the difference between the present ages of Shabnam and Mitali after 5 years will be 13 years, then what is the sum of the present ages of Mitali and Shbnam

Answers

Answered by empathictruro
2

Answer:

Sum of present ages=66

Step-by-step explanation:

Age of mitila=4x

Age of shabnam=7x

From given

7x-(4x+5) =13, solving we get x=6

So age of mitila=4*6=24

Age of shabnam=7*6=42

Sum =24+42=66

Answered by gadakhsanket
1

Hey Dear,

◆ Answer -

Sum of present ages of Mitali and Shabnam = 66 yrs

● Explanation -

Given that present ages of Mitali and Shabnam are in ratio 4 : 7. If we take x as common multiple, Mitali's age will be 4x and Shabnam's age be 7x.

Also, it's said in question -

Shabnam'age - (Mitali's age after 5 yrs) = 13

7x - (4x+5) = 13

7x - 4x - 5 = 13

3x = 18

x = 6

Sum of present ages of Mitali & Shabnam,

Mitali's age + Shabnam's age = 4x + 7x

Mitali's age + Shabnam's age = 11x

Mitali's age + Shabnam's age = 11 × 6

Mitali's age + Shabnam's age = 66 yrs

Therefore, sum of present ages of Mitali and Shabnam is 66 yrs.

Hope this helps...

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