Question

the ratio of the present age of two brother is 2 :3 ,4 years ago the ratio of their ages was 1 : 2 what is the present age of elder brother
Plzz give me correct ans plzz ​

Answer 1

Answer:

x:y=3:4 (eqn 1)

then after 5 years

ratio s-

x+5/y+5=4/5 (eqn 2)

by solvng eqn 1 and 2

we get x=15

y=20

hence the age of elder brother is 20 years

Step-by-step explanation:

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Answer 2

Let , the Age of first brother be x and second brother be y .

x 2

__= __

y 3

=> 3x = 2y

=> 3x-2y = 0 -----(1 )

4 years ago

Age of first brother = x-4

Age of second brother = y-4

x-4 1

___= ___

y-4 2

=> 2x-8 = y-4

=> 2x-y = -4+8

=> 2x-y = 4 --------(2 )×2

By combining 1 and 2

3x-2y=0

4x-2y =4

(-) (+) (-)

___________

-x = -4

x = 4

From equation 1

_______________

3x-2y=0

3(4) -2y =0

12-2y=0

-2y = - 12

y = 6

.

. . The present age of elder brother is 6 years.

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