Question

The ratio of the present age of two brothers is 1:2 and 5 years back the ratio was1:3. What will be the ratio of their age after 5 years?

Answer 1

$\textbf{Answer:}$


Ratio of present age=1:2

Let the ages of two brothers =x and 2x


$\bf{ages \: of \: 2 \: brothers \: 5 \: years \: back = \frac{x - 5}{2x - 5} } = \frac{y}{3y} \\ \\ \bf{ages \: of \: two \: brothers \: 5 \: years \: after = \frac{x + 5}{2x + 5}} \\ \\ \bf{by \: cross \: multiplication \: we \: get \: the \: 1st \: age = 10 \: years \: and \: 2nd \: age = 20 \: years} \\ \\ \bf{after \: 5 \: years \: the \: ratio \: of \: their \: ages \: will \: be = \frac{x + 5}{2x + 5} = \frac{15}{25} = \frac{3}{5} } \\ \\ \bf{the \: ratio \: after \: 5 \: years \: will \: be \: 3:5}$

$\textbf{Hope it helps you!}$