Math, asked by kajalsolanki66578, 7 months ago

The ratio of the present ages of A and B is 5:6. The ratio of their ages five years before was 45 Find their present
ages.​

Answers

Answered by MystícPhoeníx
8

Given:-

  • Ratio of Present Age = 5:6

  • Ratio of ages five years before = 4:5

To Find:-

  • The Present age of A & B.

Solution:-

Let the age of 'A' be 5x....................(i)

and, the age of 'B' be 6x.................(ii)

Now, Age of 'A' & 'B' five years before

(5x-5)/(6x-5) = 4/5 (here ratio is written in fraction)

→ (5x-5)/(6x-5) = 4/5

Cross multiplication

→ 5(5x-5) = 4(6x-5)

→ 25x-25 = 24x - 20

→ 25x-24x = -20+25

→ x = 5

Now, Substitute the value of x in equation (i) & (ii) we get

→ 5x = 5×5 = 25years

→ 6x = 6×5 = 30years

The present age of 'A' is 25 years.

And, the present age of 'B' is 30 years.

Answered by Anonymous
4

Given:-

  • ratio between the ages of A and B = 5:6
  • ratio between their ages 5 years ago = 4:5

To find:-

  • their present ages.

Supposition:-

let the age of A be 5x

let the age of B be 6x.

according to the question:-

:\implies \sf\dfrac{5x-5}{6x-5} = \sf\dfrac{4}{5}

:\implies {\sf 5(5x-5)} = {\sf 4(6x-5)}

:\implies {\sf 25x-25} = {\sf 24x-20}

:\implies {\sf x} = {\sf 5}

hence, the present age of A is 5(5) = 25 years.

and present age of B is 6(5) = 30 years.

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