Question

The ratio of the present ages of a father and her daughter is 7:1. Four years ago, the
ratio of of their ages was 19:1. What will be the daughter's age when father's age if 60?​

Answer 1

Step-by-step explanation:

fathers age=x

daughters age=y

x/y=7/1. x=7y

(x-4)/(y-4)=19/1

(x-4)=19(y-4)

x-4=19y-76

x-19y= -76+4

x-19y= -72

7y-19y= -72

-12y= -72

y=6

hence x=7y=7*6=42. x=42

To get father's age as 60 we need to add 18 years in it we get,

when x=60. then y=6+18=24

Answer 2

Answer:

Daughter's age is 24 yrs when father's age is 60 yrs.

Step-by-step explanation:

Given;

Ratio of a father's present age and his daughter = 7  : 1

Let present ages of father and his daughter be 7x and x

Four yrs ago,

Age of father = 7x- 4

Age of his daughter = x- 4

Ratio of ages of father and his daughter 4 yrs ago = 19 :1

According to the problem,

(7x - 4) /(x -4) = 19/1

7x- 4 = 19 (x -4)

7x - 4 = 19 x- 76

19x - 7x = 76- 4

12x = 72

 x= 72 /12 =6

Present age of father = 7 ×6= 42 yrs.

Present age of daughter = 6 yrs.

After (60 - 42 ) = 18 yrs age of daughter = 6 +18= 24 yrs.