Math, asked by tanush4342, 11 months ago

The ratio of the present ages of a mother and har daughter is 9:2. After 4 year the ratio of thier ages will be 10:3. From the pair of linear equation variables.

Answers

Answered by Anonymous
61

Solution :-

Let the present ages of mother and her daughter be 9x years and 2x years respectively.

After 4 years,

Mother's age = (9x + 4) years

Daughter's age = (2x + 4) years

According to the question,

=> (9x + 4)/(2x + 4) = 10/3

=> 3(9x + 4) = 10(2x + 4)

=> 27x + 12 = 20x + 40

=> 27x - 20x = 40 - 12

=> 7x = 28

=> x = 28/7 = 4

Therefore,

9x = 9 × 4 = 36 years

2x = 2 × 4 = 8 years

Answer : Present age of Mother = 36 years

Daughter's age = 8 years

Answered by Anonymous
39

LINEAR EQUATIONS IN TWO VARIABLES :

Let the present age of daughter be x year and mother be y years.

Then, Ratio => 9:2 = y : x

9/2 = y/x

9x = 2y

9x/2 = y --> ( i )

After 4 years, Ratio of their ages = 10 : 3

( y + 4 ) / ( x + 4 ) = 10/3

3y + 12 = 10x + 40

3 ( 9/2) x + 12 = 10x + 40 [ From ( i ) ]

27x/2 - 10x = 40 - 12

( 27 - 20) x/2 = 28

7x/2 = 28

x = 8 years.

Putting value of 'x' in equation ( i ),

y = 9× 8/2

y = 36 years.

Present age of daughter = 8 years.

Present age of mother = 36 years.

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