Question

The ratio of the present ages of a mother and her
daughter is 7 : 1. Four years ago, the ratio of their
ages was 19:1. What will be the mother's
age
four
(S.B.L. P.O., 2010)
years from now?​
​

Answer 1

Required Answer:-

We have:

The ratio of the present ages of a mother and her

daughter is 7 : 1

Four years ago, the ratio of their ages was 19 : 1.

To FinD:

What will be the mother's age four years from now?

Step-by-Step Explanation:

Let the ages of mother and daughter be x and y respectively.

According to condition -(1)

➛ x : y = 7 : 1

By the principle of proportion, Product of means = Product of extremes.

➛ x = 7y --------(1)

According to condition -(2)

➛ x - 4 : y - 4 = 19 : 1

Again by the principle of proportion, Product of means = Product of extremes.

➛ x - 4 = 19(y - 4)

➛ x - 4 = 19y - 76

➛ x - 19y = -72 ------(2)

Substituting x = 7y in equation (2),

➛ 7y - 19y = -72

➛ -12y = -72

➛ y = 6

Then,

x = 42

Therefore:-

The age of the mother after 4 years will be 42 + 4 =

$\boxed{\bf{46 \:years}}$

Answer 2

Step-by-step explanation:

answer is in the image...........