The ratio of the present ages of Amit and Hari is 6:7. Ten years ago, their ages were in the ratio 4:5. Find their present ages.
Answers
Step-by-step explanation:
The present age of Amit is 6x and that of Hari is 7x.
10 years ago their ages were in the ratio 4:5.
10 years ago Amit's age was (6x-10) and that of Hari was (7x-10).
Therefore,
(6x-10)/(7x-10) = 4/5
=> 5(6x-10) = 4(7x-10)
=> 30x - 50 = 28x - 40
=> 30x - 28x = 50-40
=> 2x = 10
=> x = 10/2
=> x = 5
Therefore,
Amit's present age= 6x years = 6×5 years = 30 years
Hari's present age= 7x years = 7×5 years= 35 years
Answer:
The present age of Amit is 30 years
The present age of Hari is 35 years
Step-by-step explanation:
Let,
The present age of Amit = 6x
The present age of Hari = 7x
Ten years ago,
The age of Amit = 6x - 10
The age of Hari = 7x - 10
Also,
Their ages were in the ratio 4:5
So,
⇒
⇒ 5 (6x - 10) = 4 (7x - 10)
⇒ 30x - 50 = 28x - 40
⇒ 30x - 28x = - 40 + 50
⇒ 2x = 10
⇒ x = 10 / 2
⇒ x = 5
_____________________________
★ Value of 6x :
⇒ 6 (5)
⇒ 6 × 5
⇒ 30
_____________________________
★ Value of 7x :
⇒ 7 (5)
⇒ 7 × 5
⇒ 35
Therefore,
The present age of Amit is 30 years
The present age of Hari is 35 years