Math, asked by janavedineshkumar, 10 months ago

The ratio of the present ages of Amit and Hari is 6:7. Ten years ago, their ages were in the ratio 4:5. Find their present ages.

Answers

Answered by Arka619
15

Step-by-step explanation:

The present age of Amit is 6x and that of Hari is 7x.

10 years ago their ages were in the ratio 4:5.

10 years ago Amit's age was (6x-10) and that of Hari was (7x-10).

Therefore,

(6x-10)/(7x-10) = 4/5

=> 5(6x-10) = 4(7x-10)

=> 30x - 50 = 28x - 40

=> 30x - 28x = 50-40

=> 2x = 10

=> x = 10/2

=> x = 5

Therefore,

Amit's present age= 6x years = 6×5 years = 30 years

Hari's present age= 7x years = 7×5 years= 35 years

Answered by Sauron
34

Answer:

The present age of Amit is 30 years

The present age of Hari is 35 years

Step-by-step explanation:

Let,

The present age of Amit = 6x

The present age of Hari = 7x

Ten years ago,

The age of Amit = 6x - 10

The age of Hari = 7x - 10

Also,

Their ages were in the ratio 4:5

So,

\sf{\dfrac{6x \: -  \: 10}{7x  \: - \:  \:  10}  \:  =  \:  \dfrac{4}{5}}

⇒ 5 (6x - 10) = 4 (7x - 10)

⇒ 30x - 50 = 28x - 40

⇒ 30x - 28x = - 40 + 50

⇒ 2x = 10

⇒ x = 10 / 2

x = 5

_____________________________

Value of 6x :

⇒ 6 (5)

⇒ 6 × 5

30

_____________________________

Value of 7x :

⇒ 7 (5)

⇒ 7 × 5

35

Therefore,

The present age of Amit is 30 years

The present age of Hari is 35 years

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