Question

the ratio of the present ages of mother and her son is 7 : 2 the ratio of after 7 years will be 8 : 3 what is the age of the mother 7 years ago ??​

Answer 1

Answer:

Let the present age of the mother be 7x years.

Hence, present age of son is 2x years.

__________

After 7 years....

Present age of mother = 7 x + 7 years.

Present age of son = 2 x + 7 years.

Now, the ratio of their ages is 8 : 3.

$\frac{7x \: + \: 7}{2x \: + \: 7} = \frac{8}{3}$

Cross multiplying, ....

8 [ 2x + 7 ] = 3 [ 7x + 7 ]

16 x + 56 = 21x + 21

5x = 35

x = 7.

Present age of mother = 49 years.

Present age of son = 14 years.

________

7 years ago,

Age of mother = 42 years.

Age of son = 7 years

Hope this helps....

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