Math, asked by niteshyadav100, 10 months ago

. The ratio of the present ages of Surya and Deepa is
5:6. Twelve years ago, the ratio of of the age of
1th
2
1th
4
Surya and of age of Deepa was 3 : 2. What will
be the ratio of the ages of Surya and Deepa
18 years hence?
(1) 3:4 (2) 4:3
(3) 9:8
(4) 8:9 (5) None of these​

Answers

Answered by Anonymous
7

Correct Question :

The ratio of present ages of Surya and Deepa is 6:5 . 12 years ago, the ratio of the age of Surya and Deepa was 3:2. What will be the ratio of the ages of Surya and Deepa 18 years hence ?

Given :

  • The ratio of present ages of Surya and Deepa is 6:5.
  • 12 years ago, the ratio of the age of Surya and Deepa was 3:2.

To find :

  • 18 years hence , the ratio of the ages of Surya and Deepa.

Solution :

Let the present age of Surya be 6x years and the present age of Deepa be 5x years.

12 years ago,

  • Age of Surya = (6x-12) years.
  • Age of Deepa = (5x-12) years.

According to the question :-

  • 12 years ago, the ratio of the age of Surya and Deepa was 3:2.

\implies\sf{(6x-12):(5x-12)=3:2}

\implies\sf{\dfrac{6x-12}{5x-12}=\dfrac{3}{2}}

\implies\sf{15x-36=12x-24}

\implies\sf{15x-12x=36-24}

\implies\sf{3x=12}

\implies\sf{x=4}

Now put the value of x = 4 for getting the present age of Surya and Deepa.

Present age of Surya = 6×4 = 24 years.

Present age of Deepa = 5×4 = 20 years.

After 18 years,

  • Age of Surya = (24+18) = 42 years.
  • Age of Deepa = (20+18) = 38 years.

Ratio of their ages after 18 years ,

→ 42 : 38

→ 21:19

Therefore, after 18 years, the ratio of their ages will be 21:19.

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