Question

The ratio of the present ages of two brother is 1:2and 5 yeats backthe ratio was 1:3. What will be the ratio of their ages after 5 years?

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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$<u>Your Question -</u>$

The ratio of the present ages of two brothers is 1:2. 5 years ago, the ratio was 1:3. What will be the ratio of their ages after 5 years?

$<u>Solution -</u>$

Let the present age of first brother be 'x'.
Then, present age of second brother = 2x.


5 years ago from now,

First brother's age = x - 5
Second brother's age = 2x - 5


But, according to the question, their ages will become in ratio 1:3

Then,

x-5 : 2x-5 = 1 : 3

=> x-5/2x-5 = 1/3

Cross multiplying, we get,

=> 1(2x-5) = 3(x-5)

=> 2x - 5 = 3x - 15

=> -5 + 15 = 3x - 2x

=> 10 = x

=> x = 10.

So, first brother's present age = x = 10

And, second brother's age = 2x = 2 × 10 = 20


Now, 5 years after from now

First brother's age
= x + 5
= 10 + 5
= 15 years.

And, second brother's age
= 2x + 5
= 2 × 10 + 5
= 20 + 5
= 25 years.


Now, the ratio of their ages
= 15 : 25
= 3 : 5 (dividing by 5)

$<marquee>Hence, the ratio of their ages after 5 years = 3 : 5</marquee>$
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Thank you. ;-)