Math, asked by vipulprajapati46, 4 months ago

The ratio of the present ages of two brothers is
1: 2 and 5 years back the ratio was 1: 3. What
will be the ratio of their ages after 5 years ?
(a) 1:4 (b) 2:3 (c) 3:5 (d) 5:6​

Answers

Answered by udvnishu
1

Answer:

Let the present ages of the two brothers be x and 2x years 5 years back

2x−5

x−5

=

3

1

⇒3x−15=2x−5⇒x=10

∴ The present ages are 10 years and 20 years

Required ratio=

20+5

10+5

=

25

15

=

5

3

=3:5

Answered by avniverma75
2

Step-by-step explanation:

Let their present ages be x and 2x

The ratio of their ages five years before is 1/3

their ages 5 yrs before are x -5 and 2x - 5

i.e.,

x-5/2x- 5 = 1/3

Cross Multiplying,

2x - 5 = 3x - 15

x = 10

Then, 2x = 20

Therefore, their present ages are 10 and 20 respectively.

Their ages 5 years later are 15 and 25 years.

Ratio of ages 5 yrs later = 15/25 = 3/5 = 3:5

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