Question

the ratio of the present ages of two brothers is 1 ratio 2 and 5 years back the ratio of 1 ratio 3 what will be the ratio of their ages after 5 years

Answer 1

current age of first brother = X. current age of second brother = 2x. 5 year back present age of first brother = x-5. age of second brother equals to 2 x - 5. *. x-5 / 2x-5. = 1 / 3
3x - 15. = x- 5 '. 3x - 2x. = - 5 + 15. ". X = 10.
5 years after age of first brother = X+ 5 = 15. '. 5 years after age of s second brother = 20