Question

The ratio of the price of the plots in two different areas was 2 :3 3years later the price of the plots in the first area is increased by 25 %and that in second area by 20 %the new ratio is

Answer 1

${\pmb{\frak{\underline\purple{Given:-}}}}$

• Ratio of the price of plot= 2:3

• First Increase = 25%

• Second = 20%

${\pmb{\frak{\underline\purple{Find:-}}}}$

• The new ratio

${\pmb{\frak{\underline\purple{Solution:-}}}}$

• Let, 2x and 3x

$\rm\bigstar\underline{After \: 3 \: years } :$

Price of the first plot :

$\longmapsto\rm{2x + \frac{25}{100} \times 2x }$

$\longmapsto\rm{2x + \frac{2x}{4} }$

$\longmapsto\rm{ \frac{ \cancel{10}x}{ \cancel{4}} }$

$\longmapsto\rm \boxed{ \rm\frac{5x}{2} }$

Price for Second plot :

$\longmapsto\rm{3x + 3x \: \times \frac{20}{100} }$

$\longmapsto\rm{3x + \frac{3x}{5} }$

$\longmapsto\rm \boxed{ \rm\frac{18x}{5} }$

$\sf❝ Hence \: the \: new \: ratio = \: \frac{ \frac{5x}{2} }{ \frac{18x}{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: = \frac{25}{36} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 25 : 36❞$

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Learn more:

$\begin{gathered}\begin{gathered}\begin{gathered}\end{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\small\bf\dag \: {\underline{More \: Formulae}} \\ \small\boxed{ \begin{array}{cc} \bigstar \: \sf{Gain = S.P - C.P} \\ \\ \bigstar \:\sf{Loss = C.P - S.P} \\ \\ \bigstar \: \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{loss \: \% = \Bigg( \dfrac{loss}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{S.P = \dfrac{100+Gain\%}{100} \times C.P} \\ \\ \bigstar \: \sf{ C.P =\dfrac{100}{100+Gain\%} \times S.P} \\ \\\bigstar \: \sf{ S.P = \dfrac{100 - loss\%}{100} \times C.P} \\ \\ \bigstar \: \sf{ C.P =\dfrac{100}{100 - loss\%} \times S.P}\end{array} }\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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@Shivam