the ratio of the price of two house was 16:23. Two years later when the price of the first had risen by 10% and that the second by rs 477,the ratio of their prices become 11:20 find the original price of the two house..?
Answers
Ratio of two house = 16:23
multiply by common factor x
the prices will be 16x & 23x
AFTER TWO YEARS
first house increaed by 10 % = 0.1*16x
price of the house =16x+1.6x= 17.6x
increase in other house= Rs. 477
price = 23x+477
17.6x%2F%2823x%2B477%29=11%2F20
cross multiply
352x=11(23x+477)
352x=253x+5247
352x-253x=5247
99x=5247
x=53
Price of one house= 53*16 =Rs. 848
price of second house = Rs. 1219
Answer:
hello here is ur answer
Explanation:
Ratio of two house = 16:23
multiply by common factor x
the prices will be 16x & 23x
AFTER TWO YEARS
first house increaed by 10 % = 0.1*16x
price of the house =16x+1.6x= 17.6x
increase in other house= Rs. 477
price = 23x+477
17.6x%2F%2823x%2B477%29=11%2F20
cross multiply
352x=11(23x+477)
352x=253x+5247
352x-253x=5247
99x=5247
x=53
Price of one house= 53*16 =Rs. 848
price of second house = Rs. 1219