Question

The ratio of the prices of two houses was 16:23. Two years later when the price of the first has increased by 10% and that of the second by 477, the ratio of the prices becomes 11:20. Find the original prices of the two houses.​

Answer 1

Answer:

The ratio of the prices of two fans was 16:23. Two year later when the price of the first fan had risen by 10% and that the second by 477, the ratio of their prices become 11:20. Find the original prices of two fans.

Step-by-step explanation:

Solution

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Ratio of two fans =16:23

Lets multiply by common factor x

The prices will be 16x&23x

So after two years

The price of first fan increased by 10%=0.1∗16x

The price of the fan =16x+1.6x=17.6x

The increase in price of the other fan =Rs.477

price =23x+477

Cross multiply

352x=11(23x+477)

352x=253x+5247

352x−253x=5247

99x=5247

x=53

Price of one fan =53∗16=Rs.848

price of second fan=Rs.1219

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Answer 2

Answer:

₹ 848 & ₹ 1,219

Step-by-step explanation:

Let the pries of house be ₹ 16x and ₹ 23x

As per the question,Two years later when the price of the first has increased by 10% and that of the second by 477, the ratio of the prices becomes 11:20

(16x + 10% of 16x)

$=>\frac{16x + 10\% \: of \: 16x}{23x + 477} = \frac{11}{20}\\\\=>\frac{16x + 1.6x}{23x + 477} = \frac{11}{20} \\ \\ = > 320x + 32x = 253x + 5247 \\\\ = > 352x - 253x = 5247 \\ \\ = > 99x = 5247 \\\\ = > x = 53$

Hence the original price of the house be ₹ 16 × 53 = ₹ 848

₹ 23 × 53 = ₹ 1,219