Question

the ratio of the radii of 2 right circular comes of same height is 7:3. then their volume ratio are​

Answer 1

Answer:

49:9

Step-by-step explanation:

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Answer 2

Answer:

49 : 9

Explanation:

Given that,

The ratio of the radii of 2 right circular comes of same height is 7 : 3

We need to find the ratio of their volumes.

Let's assume the radius of :-

• One cylinder = $\rm 7x$
• Another cylinder = $\rm 3x$

Volume of a cylinder is given by,

$\rm = \pi {r}^{2} h$

Where,

• ‘r’ denotes the radius and ‘h’ is the height.
• Taking $\pi$ as $\dfrac{22}{7}$

Then, volume of one cylinder :-

$\rm = \dfrac{22}{7} \times {(7x)}^{2} \times h$

$\rm = \dfrac{22}{7} \times 49x^2 \times h$

$\rm = 22 \times 7x^2 \times h$

$\rm = 154x^2h$

And also, the volume of another cylinder :-

$\rm = \dfrac{22}{7} \times {(3x)}^{2} \times h$

$\rm = \dfrac{22}{7} \times {9x}^{2} \times h$

$\rm = \dfrac{198 {x}^{2}h }{7}$

Forming in ratio :-

$\rm = 154 {x}^{2} h : \dfrac{198 {x}^{2}h }{7}$

$\rm = 154 {x}^{2} h \times \dfrac{7}{198 {x}^{2} h}$

$\rm = 154 \times \dfrac{7}{198}$

$\rm = \dfrac{1078}{198}$

$= 49 : 9$

Ratio of their volumes is 49 : 9