Question

the ratio of the radii of two bohr's orbits of H atom is 4:1. what would be their nomenclature?

Answer 1

Answer:

Explanation:

We know that the radius of nth orbit is directly proportional to that of the n^2.

Hence, from the formulae :-

Radius(r) = n^2 * 0.529/Z^2

Thus, we get to know that r is directly proportional to n^2 thus the value of r will be 16 and 1 .

So, the subshell falling under it will be K, L and N thus from this we get to know the nomenclature of the the given sample.

Answer 2

Given : ratio is 4:1 of h atom

To find : nomenclature

Explanation:

here we know that

radii of the bohr's orbit is

$0.529\times \frac{n^2}{Z}$

for H atom Z =1

and radii = 0.529× (n)²

now , for

k shell  , n=1, r = 0.529

L shell , n= 2 , r = 0.529 ×4

M shell , n= 3 , r = 0.529 ×9

N shell , n= 4 , r = 0.529 ×16

thus ,

$\frac{N}{L }= \frac{0.529\times 16}{0.529\times 4}= \frac{4}{1}\\\\\frac{L}{K }= \frac{0.529\times 4}{0.529}= \frac{4}{1}$

HENCE ,

Nomenclature of H atom is L:K or N: L

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