Question

The ratio of the salary of worker in april to that in march 5/2 : 9/4 . By what % was the salary in april more than the salary in march

Answer 1

Answer:

The salary in april is $11\frac{1}{9}\%$ more than the salary in march.

Step-by-step explanation:

The ratio of the salary of worker in april to that in march is

$\frac{5}{2}:\frac{9}{4}$

Multiply the numerator and denominator of first ratio by 2, to make the denominator common.

$\frac{5\times 2}{2\times 2}:\frac{9}{4}$

$\frac{10}{4}:\frac{9}{4}$

It can be written as

$10:9$

So, the ratio of the salary of worker in april to that in march is 10:9.

Let the salary of worker in april is 10x and the salary of worker in march is 9x.

Where have to find the salary in april is what % more than the salary in march.

$\%=\frac{\text{Salary of April-Salary of March}}{Salary of March}\times 100$

$\%=\frac{10x-9x}{9x}\times 100$

$\%=\frac{1x}{9x}\times 100$

$\%=\frac{1}{9}\times 100=11\frac{1}{9}\%$

Therefore the salary in april is $11\frac{1}{9}\%$ more than the salary in march.

Answer 2

Step-by-step explanation:

the cotrrct answer is 100/9